Compute \(C(6, 2)\) and check your answer by enumeration.

\[\binom{6}{2} = \frac{6 \cdot 5}{2!} = 15\]

The combinations are:

1. \(\{1,2\}\)
2. \(\{1,3\}\)
3. \(\{1,4\}\)
4. \(\{1,5\}\)
5. \(\{1,6\}\)
6. \(\{2,3\}\)
7. \(\{2,4\}\)
8. \(\{2,5\}\)
9. \(\{2,6\}\)
10. \(\{3,4\}\)
11. \(\{3,5\}\)
12. \(\{3,6\}\)
13. \(\{4,5\}\)
14. \(\{4,6\}\)
15. \(\{5,6\}\)